stick bow archery
You are viewing an archery tournament when you begin to wonder how fast an arrow is shot from the bow. Recalling his physics, you ask a of the archers to shoot an arrow parallel to the ground. You can find the arrow stuck in the ground 61.0 m away, making a 2.00 degrees to the ground. How fast was the arrow shot?
EDIT * Santiago, the final velocity of the arrow can not be 0! You can see this, because as you said S = t V, and if V = 0, then the arrow did not travel any reason, we know what happened 61 m! * Oh, I love this kind of questions. We will have to make a table to keep all our information line. This is a problem at two (up / down, left / right) and involves gravity. In the table, if we know the value, we will connect, Otherwise we will put in the variables. x | init y. Distance = 0 final | distance h = 61 m | 0 init. velocity = v | 0 fin. = Velocity vx | VFY acceleration = 0 | -9.8 M / s / st | t time information – the arrow is making an angle of 2.00 ° with the ground. We ignore air resistance (I assume), so acceleration in the x direction is 0. The initial velocity in the y direction is zero, since the goal keeper with the ground. A final hypothesis that we are doing the point is that the archer is standing is on the same level as when he landed on the arrow (eg, the terrain is completely flat). Generally, we use information to determine the direction and time, and from there you can determine the initial velocity of the arrow. Before you can use any of these, however, we must find the initial height of the arrow, which will require the intelligent use of trigonometry. Imagine a triangle. The arrow is a vertex of the triangle archer's feet is another, and the bow is at the height of the triangle. | _ | ___ |_____ |______ _ |______ 2 º <— |—- Arrow 61 m —— | We can find the initial height of the arrow with the equation h = tan (2nd) * 61 = 2130 m That's great, because now we can use a kinematic equation to determine the time it took the arrow to reach the ground. y = 1 / 2 g * t ^ 2 + t + h Viy * Connecting all 0 = 1.2 * (-9.8) * t ^ 2 + 0 * t + 2.13 Sovling t = 0.659 s yields from the arrow travels 61 m in 0.659 s, we have vx = 92.5 m / s. This was fun: D
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